• Congratulations to the Class of 2024 on your results!
    Let us know how you went here
    Got a question about your uni preferences? Ask us here

How to find the domain of a log function? (1 Viewer)

enigma_1

~~~~ Miss Cricket ~~~~
Joined
Feb 27, 2013
Messages
4,281
Location
Lords
Gender
Female
HSC
2014
How do I find other pieces of info enough for me to sketch the graph. Like I know the derivative stuff. But I mean like x--> infinity and stuff.

And the range?
 

Shadowdude

Cult of Personality
Joined
Sep 19, 2009
Messages
12,145
Gender
Male
HSC
2010
Domain of ln(x) is x > 0.

Replace x with whatever.


And range well... depends.

Example question?
 

hit patel

New Member
Joined
Mar 14, 2012
Messages
568
Gender
Male
HSC
2014
Uni Grad
2018
Uhh i Think derivative and limits are enough. Although you have to use the domain for inverse and trig functions
 

enigma_1

~~~~ Miss Cricket ~~~~
Joined
Feb 27, 2013
Messages
4,281
Location
Lords
Gender
Female
HSC
2014
How do i use the limit thing? Do I just test values? But it doesn't seem right to do that
 

panda15

Alligator Navigator
Joined
Feb 22, 2012
Messages
675
Gender
Male
HSC
2013
How do i use the limit thing? Do I just test values? But it doesn't seem right to do that
If you can't find the limits algebraically, then it's perfectly fine to chuck in a really big/small number to see what the limit is.
 

enigma_1

~~~~ Miss Cricket ~~~~
Joined
Feb 27, 2013
Messages
4,281
Location
Lords
Gender
Female
HSC
2014
Well, if you're just graphing it - no.
So how do you find the features of the graph like the horizontal asymptotes and the limit as x--> infinity, someone please help me lol
 
Last edited:

HeroicPandas

Heroic!
Joined
Mar 8, 2012
Messages
1,547
Gender
Male
HSC
2013
Sub in x = positive big number, y will be a big positive number

Then sub in x = negative big number, y will be a big positive number

They are the same because the curve is an even function [f(-x) = f(x)]

Then you want to know what happens at the y-axis right? Then you...?
 
Last edited:

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top