D dls1 New Member Joined May 31, 2008 Messages 3 Gender Female HSC 2009 May 31, 2008 #1 Have an equation in the form 2x/6x = ln(.75)/ln(.25) How do I solve for x?
3unitz Member Joined Nov 18, 2006 Messages 161 Gender Undisclosed HSC N/A Jun 1, 2008 #2 dls1 said: Have an equation in the form 2x/6x = ln(.75)/ln(.25) How do I solve for x? Click to expand... (2/6)^x = ln(.75)/ln(.25) ln (2/6)^x = ln [ln(.75)/ln(.25)] x ln (2/6) = ln [ln(.75)/ln(.25)] x = ln [ln(.75)/ln(.25)] / ln (2/6) Last edited: Jun 1, 2008
dls1 said: Have an equation in the form 2x/6x = ln(.75)/ln(.25) How do I solve for x? Click to expand... (2/6)^x = ln(.75)/ln(.25) ln (2/6)^x = ln [ln(.75)/ln(.25)] x ln (2/6) = ln [ln(.75)/ln(.25)] x = ln [ln(.75)/ln(.25)] / ln (2/6)
D dls1 New Member Joined May 31, 2008 Messages 3 Gender Female HSC 2009 Jun 1, 2008 #3 Thank you very much
