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HSC 2007 Q6 b Urgent help needed (1 Viewer)

Twickel

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Dec 5, 2007
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390
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HSC
2009
Hi
Q6b , how do I find the intercepts?

please solve and show working.
 

TCCPICHAMP

New Member
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Mar 15, 2008
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HSC
2009
heres the answers
(b) (i) (0,0) and (4,0).
(ii) (0,0) is a horizontal pt of inflexion.
(3,27) is a minimum T.P.
(iii) (0,0) and (2,16).
from there u should be able to work it out, if u do, it will make u remember how to do it better
 
Last edited:

Twickel

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Dec 5, 2007
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HSC
2009
I know the rest, I just cant do (i)

please do it for me.
 

Chinmoku03

Ippen, Shin de Miru?
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Australia >.<;
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HSC
2007
Sub x = 0:
f(0) = 0
So (0,0) is the point at which the curve crosses the y axis.

Sub f(x) = 0:
x4 - 4x3 = 0
x3(x - 4) = 0
x = 0 or x = 4
So (0,0) and (4,0) are points at which the curve crosses the x axis.
 

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