HSC 2012 Maths Marathon (archive) (1 Viewer)

[zeebobDD]

Re: 2U Maths marathon

new q:
prove that d/ dx(Ln(x). sqrt(cosx)) = (1-sin^2(x)/ cosx^3/2 ) - [x Ln(x) tanx sqrt(cosx)] / 2

 

[Carrotsticks]

Re: 2U Maths marathon

Use


That should make you be able to do it yourself.

Alternatively, you could recognise that it's in the t-formula form for sin(x), so the answer is simply sin(2x).

 

[twinklegal19]

Re: 2U Maths marathon

Alternatively, you could recognise that it's in the t-formula form for sin(x), so the answer is simply sin(2x).

it's 2U

so they probably only need it in 2sinxcosx?

 

[hamster-lol]

Re: 2U Maths marathon

solve for x, sinx + cosx + tanx = 1

 

[Sy123]

Re: 2U Maths marathon

For what given domain? This is 2U

Because by observation I can say x=0 is a solution.

 

[hamster-lol]

Re: 2U Maths marathon

For what given domain? This is 2U

Because by observation I can say x=0 is a solution.

-2pi < x < 2pi