nightweaver066
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- HSC
- 2012
Re: HSC 2013 3U Marathon Thread
^{n^2} = \binom{n^2}{0} + {n^2}{1}x + ... +\binom{n^2}{n^2}x^{n^2} ... (1))
^n]^n)
)
 = \binom{n^2}{2})
 = \binom{n}{0}^{n-1} \binom{n}{2} \times \binom{n}{n-1} $ (Selecting the n-1 brackets, then 1 remaining for the $ x^2 $)$)
$)


can u please reveal the solution to this question?![]()