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HSC 2015 MX2 Marathon (archive) (1 Viewer)

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Drsoccerball

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Re: HSC 2015 4U Marathon

x^2+bx+x? or x^2+bx+cx?

Solve simultaneously by subbing 2,-2,3 and setting =0 ? pre-guess :lol:
its really easy just look at the question for a bit and it will pop up
 

Ekman

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Re: HSC 2015 4U Marathon

Sounds good. Anyways next question:
The lines x=2 x= -2 y=3 are asymptotes to the curve with the equation
y=(ax^2)/((x)^2 +bc+c)
By using the above information show that:
y= (3x^2)/((x)^2 -4)
For those who still haven't understood what was going on, just find the limits of the equation y = (3x^2)/((x)^2 -4)
Since the denominator cant be equal to 0, thus x cant be equal to +2, -2
Lim x to infinity y = 3
Thus x = 2, x = -2 and y =3 are the three asymptotes.

EDIT:
Plus the question doesn't need to mention y=(ax^2)/((x)^2 +bc+c) since it directly asks for y= (3x^2)/((x)^2 -4).
 
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Drsoccerball

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Re: HSC 2015 4U Marathon

For those who still haven't understood what was going on, just find the limits of the equation y = (3x^2)/((x)^2 -4)
Since the denominator cant be equal to 0, thus x cant be equal to +2, -2
Lim x to infinity y = 3
Thus x = 2, x = -2 and y =3 are the three asymptotes.

EDIT:
Plus the question doesn't need to mention y=(ax^2)/((x)^2 +bc+c) since it directly asks for y= (3x^2)/((x)^2 -4).
Correct but the way i did it was as you said found limits for y value a=3 and wrote the x assymptotes as (x-2)(x+2) and then realized that b=0 and c is equal to -4 which gives us the equation
 

Drsoccerball

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Re: HSC 2015 4U Marathon

New question :
z is a point in the first quadrant of the Argand diagram which lies on the circle |z-3|. Given arg(z)= theta, find arg(z^2 -9z +18) in terms of theta
 

braintic

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Re: HSC 2015 4U Marathon

New question :
z is a point in the first quadrant of the Argand diagram which lies on the circle |z-3|. Given arg(z)= theta, find arg(z^2 -9z +18) in terms of theta
The circle |z-3| = what?
 

integral95

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Re: HSC 2015 4U Marathon

New question :
z is a point in the first quadrant of the Argand diagram which lies on the circle |z-3|. Given arg(z)= theta, find arg(z^2 -9z +18) in terms of theta



EDIT:yeah I'm not too sure really haha
 
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Drsoccerball

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Re: HSC 2015 4U Marathon

I don't know why im the only one posting questions but here:
 

Drsoccerball

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Re: HSC 2015 4U Marathon

ignore the < br/ > notsure why its happening
 
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