swagswagyoloswag
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- Mar 13, 2015
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- 2015
*HSC 2012
How would I do this?
(ii) Consider three identical separators to divide
the 10 coins into 4 boxes, total = 13 items, including
3 identical separators and 10 identical coins.
This was from Terry Lee's solutions, he referred to his book but I don't have it.
What's a "divider" and can someone explain his solution? as well as any other alternate solutions
How would I do this?
(ii) Consider three identical separators to divide
the 10 coins into 4 boxes, total = 13 items, including
3 identical separators and 10 identical coins.
This was from Terry Lee's solutions, he referred to his book but I don't have it.
What's a "divider" and can someone explain his solution? as well as any other alternate solutions
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