Hydrocarbons (1 Viewer)

[nsbrando]

ok i got these two questions i don't really know how to answer.

Write a balanced equation for the following reactions, draw the structural formulae and give the name of the product.

1. propene with H2O (with H2SO4 catalyst)

2. 3-hexene with bromine water

 

[Parvee]

1. It will make propanol
2. It will make dibromohexane

 

[nsbrando]

1. It will make propanol
2. It will make bromohexene

but for number 2, would it be an alkanol, because it has OH from water (H2O)???

 

[madharris]

C3H6 + H2O --> C3H7OH

C6H12 + BrOH --> C6H12BrOH alternatively C6H12 + Br2 --> C6H12Br2

i thinks that's right

 

[Parvee]

but for number 2, would it be an alkanol, because it has OH from water (H2O)???

Bromine water is just Br2(aq)

 

[madharris]

Bromine water is just Br2(aq)

Br2 + H2O --> BrOH + HBr

that's bromine water however the HSC accepts Br2

 

[nsbrando]

ok but C6H12Br2 how do i but the Br2 in to its chain, i have to substitute in the Br2 to make C6H10Br2 + H2 is this correct?

 

[nsbrando]

wait that would consider an alkyne??? IM CONFUSED!!!!

 

[Parvee]

Br2 + H2O --> BrOH + HBr

that's bromine water however the HSC accepts Br2

Yeah.
For alkene + bromine water reactions you would use Br2 as it shows the reactivity of the double bond

 

[Parvee]

ok but C6H12Br2 how do i but the Br2 in to its chain, i have to substitute in the Br2 to make C6H10Br2 + H2 is this correct?

3-hexene has a double bond in the middle. When it reacts with the bromine, the double bond breaks and the bromine joins to the chain.

 

[nsbrando]

because i have to make a structural formula, once i sub in the Br2 it removes the H2 and become an alkyne reaction, C6H10Br2 + H2

 

[nsbrando]

if the double bond breaks, will it consider as a single bond? Alkane???

 

[Parvee]

if the double bond breaks, will it consider as a single bond? Alkane???

Yes. Hence why it is 3,4-dibromohexane

 

[someth1ng]

There are many things that can be produced when reacting an alkene with bromine water.

C6H12(l)+H2O(l)+Br2(aq)-->C6H12BrOH(aq)+HBr(aq)
That is, the reaction between bromine water and 3-hexene produces 3-bromohexane-4-ol

Another possible reaction would be:
C6H12(l)+Br2(aq)-->C6H12Br2(l)

3-hexene+bromine water-->3,4-dibromohexane(l)

 

[HeroicPandas]

Question 1 - hydration

 

[someth1ng]

For question one, there are two possible products:
propane-1-ol
propane-2-ol

The location of the hydroxyl group is purely random and so, both will occur.