BraydenGay
New Member
- Joined
- Dec 5, 2007
- Messages
- 5
- Gender
- Female
- HSC
- 2010
Hi, I was just doing past papers today and I came across this loan repayments question. The problem isn't the question itself, it's the solution in the book.
It factorises: (3 x 10^6)(1.12^n) - (4 x 10^6)(1.12^n) + (4 x 10^6)
into: =(1.12^n)[(3 x 10^6)-(4 x 10^6)] + (4 x 10^6)
which is fine, and dandy but then it minuses the two things it factorises and makes:
= (4 x 10^6) - (1 x 10^6)(1.12^n)
and I thought that you couldn't do that. It seems like a fundamental thing I have forgotten, like from back in year 9...
Sorry if this sounds really stupid, rightly so. But i'm really confused. The only thing I can think of is that i'm thinking of factorising algebraic terms like:
x^2 + 2x +3
=(x-3)(x+1)
and that the reason you can't do that same thing is because you can't subtract x by 3 because x is an expression, but you can do it when they're just numbers like in the loan repayments?
thanks
It factorises: (3 x 10^6)(1.12^n) - (4 x 10^6)(1.12^n) + (4 x 10^6)
into: =(1.12^n)[(3 x 10^6)-(4 x 10^6)] + (4 x 10^6)
which is fine, and dandy but then it minuses the two things it factorises and makes:
= (4 x 10^6) - (1 x 10^6)(1.12^n)
and I thought that you couldn't do that. It seems like a fundamental thing I have forgotten, like from back in year 9...
Sorry if this sounds really stupid, rightly so. But i'm really confused. The only thing I can think of is that i'm thinking of factorising algebraic terms like:
x^2 + 2x +3
=(x-3)(x+1)
and that the reason you can't do that same thing is because you can't subtract x by 3 because x is an expression, but you can do it when they're just numbers like in the loan repayments?
thanks