I'll make u guys a deal! woth ur while ppl (1 Viewer)

[freakinout]

im having trouble with a question from the 2002 paper..... question 25) a) ii)... im ranked first in my course so i will swap u .. help for help.. anyone up for it...?

 

[padutz]

im having trouble with a question from the 2002 paper..... question 25) a) ii)... im ranked first in my course so i will swap u .. help for help.. anyone up for it...?

thats the only question i couldnt get!!! its such a bitch

 

[freakinout]

well tahn anyways.... let me know if u need anythin else.. since u were the onli one nice enuf to reply!

 

[danieljarvis]

lol i went n opened the exam.. but alas i couldnt do it either

 

[freakinout]

ok so now my end of the deal... wut do u guys want help with???? happy to do it!

 

[7th Sign]

sucess one hsc book has worked answers maby look their

 

[danieljarvis]

id love help in finding tomorrows paper tonight?

 

[7th Sign]

would love to help but my sucess one books down stairs atm

If you came first it should not be that hard just post up the question on this forum and people will work through it very fast!

 

[Casmira]

oh christ i hate that question

its somethign to do with the ratio of sizes

 

[danieljarvis]

haha fuck thats a gay questino

 

[chamelia]

d/200 = 20/x

 

[fugazi]

Since EAD and CAB are similiar...

d/200 = 20/x

Therefore, d = 20/x x 200
d = 4000/x

or x = 4000/d.

 

[freakinout]

thanx for trying but i still don get it... so much for being first in course ... its not showing... lol ..... anymore questions guys?

 

[7th Sign]

that question is not that hard compared to some 2 unit bs i did in year 11

oh well i would probly stuff up something in it and get shit marks for that q lol

 

[100percent]

thanx for trying but i still don get it... so much for being first in course ... its not showing... lol ..... anymore questions guys?

rofl, this may be a bit late of a reply, but
similar triangles.
2 angles common, so 3rd angle must be common,
(both share a common angle and both have a 90 degree angle)
that is, equalangular.

take the proportion of the triangle
ie d/200=20/x
xd=4000
d=4000/x
relationship, as x increasing, d decreases

 

[Muzzaw]

Q 25 (a) (i)

(1) Similar figures = ACB, AED

(2) Enlargement factor = AC/AE
= 200/50
= 4

(3) CB = 20 x 4
= 80 cm

Trig. is my bitch.

 

[H.S.What?]

im pretty sure q25 ii) has something to do with inverse variation rather than scale factor as d varies inversely with x. I just havnt figured out the formula yet

x varies inversely with d
therefore, x = ? / d

i dunno wat the ? number is

 

[H.S.What?]

rofl, this may be a bit late of a reply, but
similar triangles.
2 angles common, so 3rd angle must be common,
(both share a common angle and both have a 90 degree angle)
that is, equalangular.

take the proportion of the triangle
ie d/200=20/x
xd=4000
d=4000/x
relationship, as x increasing, d decreases

sorry i didnt see 100percent's reply, he/she is right.