Imaginary No (1 Viewer)

Lukybear · Oct 25, 2009

Solve equation for z, express answer in the form a+ib(z+3)/(z-1) = 2-3i... i dunno how to approach the simultaneousAlso, if we get two answers, how do we check if one is wrong?

untouchablecuz · Oct 25, 2009

Dumbledore · Oct 26, 2009

i think the a+ib is seperate from the equation

u just multiply across, expand, collect and factorise the terms with z, divide by coeffient of z , then realise the denominator

ninetypercent · Oct 26, 2009

(z+3)/(z-1) = 2-3i

this question came from patel. I didn't get the correct question too.
i dunno, maybe

$\frac{z -1 + 4}{z - 1} = 2 - 3i$
$1 + \frac{4}{z -1} = 2-3i$
$\frac{4}{z-1} = 1 - 3i$
$\frac{4}{1-3i} = z - 1$
$\frac{4}{1-3i}.\frac{1 +3i}{1+3i} = z - 1$
$\frac{4+12i}{1-9i^2} = z - 1$
$\frac{4+12i + 10}{10} = z$
$z = \frac{14 + 12i}{10} = \frac{7+6i}{5}$

Imaginary No (1 Viewer)

Lukybear

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untouchablecuz

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Dumbledore

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ninetypercent

ninety ninety ninety

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