Increasing function (1 Viewer)

[machine2035]

Guessing it has something to do with f'(x) > 0 ?

I got as far as finding f'(x) and thats it.

Cheers.

 

[Carrotsticks]

We indeed want f'(x) > 0, for all x.

So we differentiate f(x) (we get a quadratic), then let the discriminant be less than zero. By doing this, you always have the quadratic being positive and hence f'(x) > 0.

 

[machine2035]

We indeed want f'(x) > 0, for all x.

So we differentiate f(x) (we get a quadratic), then let the discriminant be less than zero. By doing this, you always have the quadratic being positive and hence f'(x) > 0.

Awesome, cheers.

Ended up getting k < 3