Industrial Chem (2 Viewers)

[kaz1]

I thought this section was pretty easy. What did everyone get for the K value. I got 5.something.

 

[boxhunter91]

Yeh i got 5. something aswell.
It was ok just forgot the structure of glycerol.

 

[goby]

Yes I got 5.x for the K value as well.

I thought the whole section was relatively easy o.0.

 

[Monsterman]

I failed to get K cause i think i put it into the calculator wrong.... but got the rest..

 

[imsleepyz]

5. something? damn i got 0.15 something anyone else got that?

 

[carlytse621]

5. something? damn i got 0.15 something anyone else got that?

lol~ i got 0.something too : S

 

[Tastegud]

0.18 anyone?
Only way to get a number >1 was if you had products over reactants I think...

Yeahp, just calculated. 1/0.18 = 5.55555
You guys do it the wrong way around?


Oh just wna say: easiest industrial ever.

 

[imsleepyz]

did anyone get 0.45^3 times 0.15 / 0.30^2 = 0.151875??


please tell me that somebody has that

 

[lizajane91]

0.18 anyone?
Only way to get a number >1 was if you had products over reactants I think...

Yeahp, just calculated. 1/0.18 = 5.55555
You guys do it the wrong way around?


Oh just wna say: easiest industrial ever.

nah pretty sure it was 5 something...cant remember the exact values but did u do the whole (initial value - 2x) etc etc to take into account the value once it had reached equilibrium
my bad if this doesnt make sense its hard to remember without the q sheet

 

[C-BAS]

I forgot how to draw glycerol, along with maybe 2-3 marks for some of the saponification shit.

Pumped the last question though.

Maybe 20/25? Pretty good for me.

 

[boxhunter91]

It is [0.453]^3[0.15] / [0.05]^2 = 5.4675

 

[imsleepyz]

damn it is 5. something i put the change as 0.05 and final as 0.3 damn
guess 3 marks gone for industrial

 

[Tastegud]

0.18 anyone?
Only way to get a number >1 was if you had products over reactants I think...

Yeahp, just calculated. 1/0.18 = 5.55555
You guys do it the wrong way around?


Oh just wna say: easiest industrial ever.

I'm a retard.

why the fuck did i think it was reactants on products?
fuck my life.:rofl:

never visiting this thread again. it just depressed me.

 

[decapitated]

yeah i got like 0.12- fucked that up

 

[danal353]

did anyone get 0.45^3 times 0.15 / 0.30^2 = 0.151875??


please tell me that somebody has that

I got exactly that!... but everyone else seems to have gotten 5...

 

[TechnIx]

I thought this section was pretty easy. What did everyone get for the K value. I got 5.something.

5.4765

Yeh i got 5. something aswell.
It was ok just forgot the structure of glycerol.

Haha unlucky. C3H5(OH)3.....It's like an E shape

did anyone get 0.45^3 times 0.15 / 0.30^2 = 0.151875??

please tell me that somebody has that

Errr lol. Looks like you messed up the 0.30, it should be 0.05.

I know what you did wrong, you were meant to SUBTRACT 0.30 from 0.35.

Here's the table: ..... NOTE: In brackets means subscript
................2ICl(3) >> I(2) + 3CL(2)
Initially.....0.35__>>__0____0
@ Equil.....-0.3__>>_+0.15_+0.45
.:. ............0.05__>>_0.15__0.45

Then sub those into K equation

It is [0.453]^3[0.15] / [0.05]^2 = 5.4675

You made a typo. It's 0.45^3, not 0.453^3

 

[Thecorey0]

I got 5.something for the constant. I quite liked the questions. The 7-marker was a repeat of past years though, was the same as my trial as well.

 

[imsleepyz]

its 5.something coz the final con. of icl3 is 0.35-0.30= 0.05 not 0.30 =.= fken gay wrote 0.30

 

[imsleepyz]

do i lose 2 or 3 marks?

 

[shaon0]

I thought this section was pretty easy. What did everyone get for the K value. I got 5.something.

yeah, it was really easy which is good.