theprofitable95
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Prove that
a/b +b/c +c/a is greater than or equal to 3, where a,b and c are positive numbers.
Just can't figure out how to do this one.
I also have a question about inequalities in general. When writing a proof, do we always have to start from a known statement and then reach the statement, or can we just manipulate the original expression, writing 'required to prove' as we go.
I'll use an easy example question. Prove that a^2 + b^2 >2ab
METHOD 1
R.T.P a^2-2ab+b^2>0
RTP. (a-b)^2>0
since result here is obvious, statement has been proved.
OR in exam conditions do i have to re-write this in reverse:
ie. METHOD 2
it is known that (a-b)^2>0
a^2 - 2ab +b^2>0
a^2 +b^2 > 2ab, thus statement is true.
a/b +b/c +c/a is greater than or equal to 3, where a,b and c are positive numbers.
Just can't figure out how to do this one.
I also have a question about inequalities in general. When writing a proof, do we always have to start from a known statement and then reach the statement, or can we just manipulate the original expression, writing 'required to prove' as we go.
I'll use an easy example question. Prove that a^2 + b^2 >2ab
METHOD 1
R.T.P a^2-2ab+b^2>0
RTP. (a-b)^2>0
since result here is obvious, statement has been proved.
OR in exam conditions do i have to re-write this in reverse:
ie. METHOD 2
it is known that (a-b)^2>0
a^2 - 2ab +b^2>0
a^2 +b^2 > 2ab, thus statement is true.