Integral of a quarter-circle (1 Viewer)

[Heresy]

Find the area bounded by the curve y = (4-x^2)^1/2, the x-axis and the y-axis in the first quadrant.

I know what the integral is, but whenever I try to solve it I end up with 16/3 - when the answer should be pi units^2

Any help would be appreciated. Thanks.

 

[HeroWise]

 

[Heresy]

Cheers!

 

[fan96]

something that should be explicitly noted is that



(and in general, )

usually the bounds of the integral will mean that but one should still be careful when dealing with situations like this.

 

[HeroWise]

Yes definetly, i have been in situations where i got that wrong lol. aka Weird vector questions which has both multiple positive cases and the negative cases which i missed because of that silly thing

 

[Heresy]

something that should be explicitly noted is that



(and in general, )

usually the bounds of the integral will mean that but one should still be careful when dealing with situations like this.

Thank you.

On a completely unrelated note - how do you type in that font with the equations - I'm curious lol - it will make it 10 times easier next time I inevitably ask for help

 

[fan96]

Thank you.

On a completely unrelated note - how do you type in that font with the equations - I'm curious lol - it will make it 10 times easier next time I inevitably ask for help

It's called tex.

Here is a good guide to get started: http://community.boredofstudies.org/10/maths/234259/short-guide-latex.html