• Best of luck to the class of 2024 for their HSC exams. You got this!
    Let us know your thoughts on the HSC exams here
  • YOU can help the next generation of students in the community!
    Share your trial papers and notes on our Notes & Resources page
MedVision ad

Integrate e^x with me (1 Viewer)

independantz

Member
Joined
Apr 4, 2007
Messages
409
Gender
Male
HSC
2008



hey if you read up, i got the same thing as you, and i treated i as a constant because it came from square root of -1 ??
That's not his solution, his saying that your solution is equivalent to mine, as we both assumed i to be a constant.
 

lolokay

Active Member
Joined
Mar 21, 2008
Messages
1,015
Gender
Undisclosed
HSC
2009
^it's correct, but i don't think you can assume it
 

Templar

P vs NP
Joined
Aug 11, 2004
Messages
1,979
Gender
Male
HSC
2004
So i could not integrate:
S [limits: 2i to i] x dx
= 0.5(2i)^2-0.5(i)^2
= -2+0.5
= -1.5
You need to define a path from i to 2i and do a contour integral.

The problem is that all your (high school) functions are real functions, and you are doing real analysis with them. There is no logical reason why you can simply extend them to complex functions and complex variables.

Take this example: just because you can use induction on the (positive) integers, can you use it on the rationals or the reals?
 

shaon0

...
Joined
Mar 26, 2008
Messages
2,029
Location
Guess
Gender
Male
HSC
2009
You need to define a path from i to 2i and do a contour integral.

The problem is that all your (high school) functions are real functions, and you are doing real analysis with them. There is no logical reason why you can simply extend them to complex functions and complex variables.

Take this example: just because you can use induction on the (positive) integers, can you use it on the rationals or the reals?
Ah cool. Even though i haven't done induction i get your point.
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top