That is definitely not a 2U integration questionIt is 2U, can you help me with another one, 1/x+4?
It is 2U...That is definitely not a 2U integration question
And its ln(x+4) + C
...but you learn to do them later on.Then why are all these questions coming up in 2U papers?
That's incorrect, you will learn how to do such questions when you do logs.1/ (x+4)
= (x+ 4)^ -1
= (x + 4) ^1 / 1 + c
= (x+4) + c
(i think). i do 2 unit, btw.
really? you meanIt is 2U...
oh sorry i thought you meant the log one.really? you mean
?
I highly doubt it... unless I'm reading it wrong