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integrating and differentiating sin^2(x) and cos^2(x) (1 Viewer)
- Thread starter helz_h
- Start date
Trev
stix
d/dx * sin<sup>2</sup>x = 2cosx.sinx
d/dx * cos<sup>2</sup>x = -2sinx.cosx
Like you know how cos<sup>2</sup>x+sin<sup>2</sup>x=1
d/dx * [cos<sup>2</sup>x+sin<sup>2</sup>x] = d/dx * 1
2cosxsinx - 2sinxcosx = 0
0 = 0
d/dx * cos<sup>2</sup>x = -2sinx.cosx
Like you know how cos<sup>2</sup>x+sin<sup>2</sup>x=1
d/dx * [cos<sup>2</sup>x+sin<sup>2</sup>x] = d/dx * 1
2cosxsinx - 2sinxcosx = 0
0 = 0
onebytwo
Recession '08
for integration
make since cos2x=(1/2)(1+cos2x)...then integrate
do the same thing for sine
make since cos2x=(1/2)(1+cos2x)...then integrate
do the same thing for sine
