• Congratulations to the Class of 2024 on your results!
    Let us know how you went here
    Got a question about your uni preferences? Ask us here

Integration Q: Sums and Differences of Areas (1 Viewer)

hc.pmt

New Member
Joined
Nov 12, 2008
Messages
16
Gender
Female
HSC
2011
Hey guys,
can anyone help me with this question - its been doing my head in for a while.
Its question 13, Ex. 3.8. of Maths In Focus:

Find the area bounded by the curve y = x² + 2x - 8 and the line y = 2x + 1

Any help is appreciated - worked solutions even more so :]
 

hc.pmt

New Member
Joined
Nov 12, 2008
Messages
16
Gender
Female
HSC
2011
can someone please explain WHY i have to deduct the curve from the line?
 
Last edited:

sazlik

Flailing Nerd
Joined
Nov 8, 2008
Messages
20
Gender
Female
HSC
2011
The area between the two curves is the difference between the areas of the two curves. (If you don't know which curve is above the other then you need to use the absolute value to obtain a positive area.)



This is true for all positions of the curves—so long as they don't cross each other between x=a and x=b.

Hope that helps?
 

hscishard

Active Member
Joined
Aug 4, 2009
Messages
2,033
Location
study room...maybe
Gender
Male
HSC
2011
The area between the two curves is the difference between the areas of the two curves. (If you don't know which curve is above the other then you need to use the absolute value to obtain a positive area.)



This is true for all positions of the curves—so long as they don't cross each other between x=a and x=b.

Hope that helps?
:confused::confused:
I would sketch it. Then see which is above which. If I still can't find it, I'll just sub a value in both equations that is between the points of intersection. Then which ever is greater, must be on top[Therefore it is g(x) in Integral: g(x)-f(x)]

Is there a quicker way?
 

sazlik

Flailing Nerd
Joined
Nov 8, 2008
Messages
20
Gender
Female
HSC
2011
:confused::confused:
I would sketch it. Then see which is above which. If I still can't find it, I'll just sub a value in both equations that is between the points of intersection. Then which ever is greater, must be on top[Therefore it is g(x) in Integral: g(x)-f(x)]

Is there a quicker way?
It doesn't matter which you subtract from the other, really—so long as you take the absolute value (because area can't be negative.) You get the same magnitude either way—only the sign differs. I'm almost 100% sure I'm right on this, but if I'm not please feel free to correct me otherwise. :)
 

sazlik

Flailing Nerd
Joined
Nov 8, 2008
Messages
20
Gender
Female
HSC
2011
Nope, I didn't make it up. Our teacher told us...but yep, it's in our textbook too. :) 3 Unit Mathematics Book 1, Jones & Couchman. (Published by Longman.)
 

sazlik

Flailing Nerd
Joined
Nov 8, 2008
Messages
20
Gender
Female
HSC
2011
Oh, that is—I have the combination advanced/extension book, but the same chapter is also in the 2 Unit Book 1, I'm pretty sure.
 

bouncing

Member
Joined
Mar 19, 2010
Messages
497
Gender
Female
HSC
2010
yup sazlik is 100% correct...

it makes no difference what order the curves are subtracted as long as there is an absolute value outside.. i think this method (of using absolutes) is incredibly fast when it comes to those annoying curves that cannot be drawn (or if you are one who has trouble identifying which is above the other)

pps i got 36 units as well :D
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top