S [0,4] (x+4-4)/sqrt(x+4) dx = S [0,4] sqrt(x+4) dx - S [0,4] 4/sqrt(x+4) dxintegrate between 4 and 0 x / root(x+4) dx
ty
let u = x+4 ?
thanksS [0,4] (x+4-4)/sqrt(x+4) dx = S [0,4] sqrt(x+4) dx - S [0,4] 4/sqrt(x+4) dx
or this^u2=x+4 looks more neat imo.
not sure about the complete the square bit but integrte x + 4 + 2/xintegrate (x^2 + 4x +2) / x dx
under completing square topic once again
etcintegrate between 4 and 0 x / root(x+4) dx
ty
hmm ill guess ill just do it like that thennot sure about the complete the square bit but integrte x + 4 + 2/x
arent these these spose to be really easy?? o.o
Big boys use implicit differentiation.
Thus, integral becomes (with already changed limits):
...and you can do the rest since it's early in the morning.
LOL!Big boys use implicit differentiation.
Well in 4 unit they expect a little more understanding from you, so implicit differentiation demonstrates that a little more, and saves time in particularly complicated examples.LOL!
but isn't it always implicit differentiation anyways?
like
2y = 3x + 1
y = 3/2x + 1/2
dy/dx = 3/2
OR
2y = 3x +
2 dy/dx = 3
dy/dx = 3/2