ashokkumar
Mr
Find the area bounded by the curve y = e^x/(1+e^2x), the x-axis, the y-axis and the ordinate x = 1/2ln3.
Integration. (1 Viewer)
- Thread starter ashokkumar
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Your answer is right but your upper limit is meant to be 1/2.ln(3)^{2}}\ de^{x}\\ \\ =\ \ \left [ tan^{-1}e^{x} \right ]^{ln\sqrt{3}}_{0}\ \ =\ \ tan^{-1}e^{ln\sqrt{3}}-tan^{-1}e^{0}\\ \\ =\ \ tan^{-1}\sqrt{3}-tan^{-1}1\ \ =\ \ \frac{\pi }{3}-\frac{\pi }{4}\ \ =\ \ \frac{\pi }{12})
Yes but 0.5 ln 3 is the same as ln(sqrt(3)); otherwise it'd be very unlikely I'd have got the right answer.