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With that working, you should get it, but the wording might cost you mark.oh foot nuts!
i just realised i got all the working out BUT, i concluded that "therefore, when intensity is doubled, loudness increases by x1.077"
IE L2/L1 = 1.077
i realised that 1.077 x 90 = 6.93,
so wrong or right?
heya yeah.. my brother just explained it to me,This is what I did. I'd appreciate it if somebody could tell me if I did something wrong.
Normal Intensity:
Double Intensity:
times louder
That works, i evaluated it as a bloody percentage instead of a differenceI stated that i wanted intensity to equal 1
I just made 2 = e^0.1 L
In 2 / 0.1 = L
L = what ever the answer is.
I think I did the above, then evaluated as a % increase.That works, i evaluated it as a bloody percentage instead of a difference![]()
I think I did the above, then evaluated as a % increase.
Yeah I got that as well.Yes I second 10ln2.
I left it exact cos they didn't ask for an approximation ... at least from what I can recall.