Intergration Question (1 Viewer)

[sloveni]

Hi everyone. Just wondering if anyone can answer this question...
ok this is the exact phrase:

Find the area bounded by the curve x^2 -x-2, the x-axis and the lines x=1, x=3.

The answer is 3 units squared

Thanx(solved)


EDIT- New Question

Hi i was wondering how u can change y=(x+3)^2 to the subject of x

thanx agian

 

[js992]

If you draw it out, you will notice that the parabola crosses the x axis at 2. As you want the area from x = 3 to x=1, you must take the areas separately

Total area = |Area 1| + Area 2

For area 1 , for the integral from 2 to 1, then use take the absolute value of it as you cannot have a negative area

Find area 2 by taking the integral from 3 to 2

Add them together and you will get 3.

 

[sloveni]

thanx mate

 

[pman]

use the absolute values of both areas though, just reduces the chance of a mistake in the exam

 

[sazlik]

For your new question:



I assume that's correct. It's all just a process of working backwards. (And of course, you don't need to use an indice instead of a square root sign, but it might make it easier depending on the question.)