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Inverse Functons (1 Viewer)

steve001

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Oct 19, 2008
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2009
Hey, im got having trouble drawing the graph for this function:

Consider the function f(x)=3cos to the power of -1(2x)
(i) state the domain and range
D = -.5 - x - .5
R = 0 - y - 3pi
Sketch the graph, showing all important features
 

Casper_18

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and then just use the equation in terms of x to draw your graph and rember the restricted d & r when you draw it.
 

kurt.physics

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Hey, im got having trouble drawing the graph for this function:

Consider the function f(x)=3cos to the power of -1(2x)
(i) state the domain and range
D = -.5 - x - .5
R = 0 - y - 3pi
Sketch the graph, showing all important features


Now consider





So the domain of :





The range of is

ie

therefore the range of is



(as it seams you found)

The following image is taken from wikipedia, the blue line shows the general graph of




So to graph we start at the extreme value of the domain (ie the x-intercept) which is .

The y intercept occurs half way inbetween the maximum range, ie

And of course when

So just draw the graph based on this information. It will look pretty much like the blue graph above just with different y/x intercepts.

You could also just simply draw and visually flip it through just to get an idea. But for some this is hard and also not an acceptable solution in an exam, merely just a method to get a general understanding of the graph =)
 
Last edited:

steve001

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Oct 19, 2008
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2009
Thanks for the help people, i understand how to draw it now
 

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