inverse trig graph qn (range) (1 Viewer)

[Masaken]

how would you find the range of this graph ?

i feel like it's easy but it's just not coming to me, i know usually you use the original range of the default inverse cos curve (0 to pi), but i'm not so sure how to use it here. i have the domain if it's important (x is less than or equal to -1, or greater than or equal to 1)... thanks in advance

 

[Masaken]

nevermind, i think i got it... it's just doing lim x-> plus minus infinity, then i get a HA from there. oops

 

[Drongoski]

So what is your answer for the range?

 

[Masaken]

So what is your answer for the range?

[0, pi/2) U (pi/2, pi] I believe the answer is that
pi/2 is the HA, and the function is never below the x axis