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y= arccos(cosx)can someone show me a method of findin domain and range and sketching graph of these functions
y= arccos(cosx)
y=cos(arccosx)
y=arctan(tanx).....thanks in advance
thanks anyways u did clear some of my doubts but how did u get all real x as domain for the first oneOh I just saw you wanted an explanation, somebody may have to do this for me, a bit busy now.
If nobody does by tomorrow, I'll finish it off.
Think about it like this. Is there any value of x that you can sub in that makes the expression undefined? cosx is defined for every value of x and will give a value between -1 and 1. arccos is defined between -1 and 1, therefore all values of x will give a valid value (this isn't phrased well) that will allow arccos(cosx) to be defined.thanks anyways u did clear some of my doubts but how did u get all real x as domain for the first one
Yep, didn't change brackets when I copy/pasted.For 1st one: cosx can take any real value of x (its value would go from -1 to +1 to -1 ... repeatedly) and range will be [0,pi] if I'm still awake. And if I'm still awake, the range for the last one is (-pi/2, pi/2) rather than [-pi/2. pi/2]