Since element B has the highest first IE amongst the four consecutive elements, it must be a noble gas. Thus:
- element A is a halogen (group 17) and forms an A- anion
- element C is in group 1 and forms a C+ cation
- element D is in group 2 and forms a D2+ cation
Forming a D
3+ cation requires
much more energy than is needed to form D
2+. Since an atom of element D has 2 electrons in its valence shell, the D
2+ cation has emptied that valence shell and its outermost electron shell is now a complete / filled shell that was formerly an inner shell. We can predict that the 2nd IE of D was perhaps double its 1st IE, whereas its 3rd IE will be much higher, perhaps five to ten times that of the 2nd IE, and so the formation of the D
3+ cation is very unlikely.