Just Wondering ... Exam Preparation (1 Viewer)

[rokkuran-x]

I've got my first 4u exam next friday on polynomials and complex numbers and i was just wondering if people could leave me some questions to do for some preparations for that exam

ive done 2 textbooks exercises but im like worried that my teacher will throw curly ones in there but he says its "really easy" but he always says shit like that

much appreciated

 

[kevda1st]

wth? first exams?? shouldnt u be having ur half yearlys??

mines in 4 weeks and its got 5 chapters in it...

oh and about questions, ill get back to u

 

[rokkuran-x]

we got half yearlys soon too in 4 weeks or so

weve done 3 topics - graphs polynomials and complex numbers but the for the first examination its just those two. were doing integration now then conics i think

 

[Timothy.Siu]

lols my first 4unit exam is next term

 

[vds700]

I've got my first 4u exam next friday on polynomials and complex numbers and i was just wondering if people could leave me some questions to do for some preparations for that exam

ive done 2 textbooks exercises but im like worried that my teacher will throw curly ones in there but he says its "really easy" but he always says shit like that

much appreciated

here u go, these files have a few topics each, so u might need to scroll down to find complex no.s and poly's

 

[rokkuran-x]

much appreciated once again

 

[youngminii]

Past papers.

 

[kevda1st]

Past papers.

no shit

scanned a past conics paper i got. Hope it helps, the last question is a bitch

http://i237.photobucket.com/albums/ff210/kevda1st/img018.jpg

 

[P.T.F.E]

i had my first exam last thurs day and now i have a half yearly in 5 weeks. personally i think its stupid!

 

[jchoi]

Here is an easy one:

Factorise over C.
It'll be in ur test 100%, something of the likes.

 

[shaon0]

Here is an easy one:

Factorise over C.
It'll be in ur test 100%, something of the likes.

Tjis'll be revision for my polynomials.
z=x^3-1
=(x-1)(x^2+x+1)
Roots of x^2+x+1 are: cis(2pi/3) and cis(-2pi/3)
Thus, z=(x-1)(x-cis(2pi/3))(x-cis(2pi/3))