kJ/mol (1 Viewer)

[Tommy_Lamp]

I have this question that asks


"A student found that 2.8g of butane burned to give out 72.4kJ of energy, calculate the the enthalpy of combustion of butane in kJ/mol"

the mm of butane is 58.12, so do you divide 72.4 by 58.12?

 

[mushroom_head]

mol of butane= 2.8/58.12 =0.048

therefore 0.048 mol produces 72.4KJ

72.4/0.048 = 1502.8 KJ/mol

can someone confirm this?

 

[Xayma]

Mushroom head yes your right, but the enthalpy of combustion is expressed as a -ve number.

 

[Tommy_Lamp]

ok sweet, thankyou