limits (1 Viewer)

hello-there · Apr 8, 2010

shaon0 said:
I=S e^(1/x)/x^2 dx
=-e^(1/x)+C

nice
but how did you do it?

also how do you integrate Square troot x e^(xrootx)

nikkifc · Apr 8, 2010

hello-there said:
also i got another question by its integration how do you integrate
$\int \exp ^1^/^x/x^2dx$

Let u=1/x

du/dx = -1/x^2

$\therefore \text{ Integral, I }=\int e^u .-du = -e^u+c = -e^{1/x}+c$

tommykins · Apr 8, 2010

hello-there said:
also i got another question by its integration how do you integrate
$\int \exp ^1^/^x/x^2dx$

$\int \frac{e^{\frac{1}{x}}}{x^2} dx\text{ can be observed as}\\ \int f'(x).f(x)dx\text{ in which case}\\ \int \frac{e^{\frac{1}{x}}}{x^2} dx = {-e}^{\frac{1}{x}}+C$

shaon0 · Apr 8, 2010

hello-there said:
nice
but how did you do it?

also how do you integrate Square troot x e^(xrootx)

I= S sqrt(x)e^(xsqrt(x)) dx
= S sqrt(x)e^(x^(3/2)) dx
Let u=x^(3/2):du=3/2 x^(1/2) dx
I= 2/3 S e^u du
=2/3 e^u +C
=2/3 e^(xsqrt(x)) +C

limits (1 Viewer)

hello-there

Member

nikkifc

Member

tommykins

i am number -e^i*pi

shaon0

...

Users Who Are Viewing This Thread (Users: 0, Guests: 1)