? =)(= Active Member Joined Jul 14, 2021 Messages 647 Gender Male HSC 2023 Sep 23, 2022 #1 why cant you take 8i cause wouldnt arg there be undefined
C cossine Well-Known Member Joined Jul 24, 2020 Messages 626 Gender Male HSC 2017 Sep 23, 2022 #2 =)(= said: View attachment 36337 why cant you take 8i cause wouldnt arg there be undefined Click to expand... I thought 8i cannot be included because you wouldn't have a vector?
=)(= said: View attachment 36337 why cant you take 8i cause wouldnt arg there be undefined Click to expand... I thought 8i cannot be included because you wouldn't have a vector?
T tywebb dangerman Joined Dec 7, 2003 Messages 2,206 Gender Undisclosed HSC N/A Sep 23, 2022 #3 =)(= said: View attachment 36337 why cant you take 8i cause wouldnt arg there be undefined Click to expand... It doesn't matter. If z=8i then Re((z-8i)/(z+6))=0 and so 8i is included in the locus. arg((z-8i)/(z+6))=π/2 or 3π/2 only applies to most values of z on the locus, but not necessarily all of them. In particuar it doesn't apply if z=8i. Last edited: Sep 23, 2022
=)(= said: View attachment 36337 why cant you take 8i cause wouldnt arg there be undefined Click to expand... It doesn't matter. If z=8i then Re((z-8i)/(z+6))=0 and so 8i is included in the locus. arg((z-8i)/(z+6))=π/2 or 3π/2 only applies to most values of z on the locus, but not necessarily all of them. In particuar it doesn't apply if z=8i.
? =)(= Active Member Joined Jul 14, 2021 Messages 647 Gender Male HSC 2023 Sep 23, 2022 #4 wait but why wont it apply to 8i
T tywebb dangerman Joined Dec 7, 2003 Messages 2,206 Gender Undisclosed HSC N/A Sep 23, 2022 #5 Re((8i-8i)/(8i+6))=0 so 8i is part of the locus but arg((8i-8i)/(8i+6))=arg(0) which is undefined.
? =)(= Active Member Joined Jul 14, 2021 Messages 647 Gender Male HSC 2023 Sep 23, 2022 #6 ohhh i get it now thanks so much, so for the same reason 6 is not included cause re(undefined)
