log help (1 Viewer)

[simDS]

find the 2nd derivative of y= loge (x/2)

 

[kaz1]

1st derivative= 1/x
2nd= -1/x²

 

[simDS]

1st derivative= 1/x
2nd= -1/x²

what happens to the loge 2 how do u derive thaT?

 

[kaz1]

Derivative of a log_e is f'(x)/f(x) so the first derivative is (1/2)/(x/2) which simplifies down to 1/x.

 

[oly1991]

what happens to the loge 2 how do u derive thaT?

the derivative of (x/2) is 1/2. so u put that on top of x/2 and it ends up being 1/x.

 

[Timothy.Siu]

or just do

y=ln (x/2)=ln x - ln2
y'=1/x
etc.