S steve001 Member Joined Oct 19, 2008 Messages 48 Gender Male HSC 2009 Mar 24, 2009 #1 hey, does anybody know how to do this question: Show that the derivative of y = ln(x-3) - ln(x+3) is given by 6 over x^ - 9 Thanks in advance
hey, does anybody know how to do this question: Show that the derivative of y = ln(x-3) - ln(x+3) is given by 6 over x^ - 9 Thanks in advance
GUSSSSSSSSSSSSS Active Member Joined Aug 20, 2008 Messages 1,102 Location Turra Gender Male HSC 2009 Mar 24, 2009 #2 derivative of ln(x-3) = 1/(x-3) derivative of ln(x+3)=1/(x+3) just simplify, common denominator etc 1/(x-3) - 1/(x+3) =(x+3 - (x-3))/(x-3)(x+3) =6/(x^2-9) XDD
derivative of ln(x-3) = 1/(x-3) derivative of ln(x+3)=1/(x+3) just simplify, common denominator etc 1/(x-3) - 1/(x+3) =(x+3 - (x-3))/(x-3)(x+3) =6/(x^2-9) XDD
S steve001 Member Joined Oct 19, 2008 Messages 48 Gender Male HSC 2009 Mar 24, 2009 #3 hey thanks man, didnt even think of it that why Last edited: Mar 24, 2009