leehuan
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Re: MATH2601 Linear Algebra/Group Theory Questions

I have most of the proof covered up but I'm getting confused at the last bit.

\textbf{v}=0\textbf{v}=\textbf{0}&=-\alpha\textbf{v}\\ \therefore \alpha\textbf{v}&=-\alpha\textbf{v}\end{align*})
&= \alpha^{-1}(-\alpha\textbf{v})\\ \textbf{v}&=-\textbf{v}\\ 2\textbf{v}&=0\\ \textbf{v}&=0\end{align*})
All I'm really stuck on is how to prove that if v \neq 0 why must alpha be equal to 0
I have most of the proof covered up but I'm getting confused at the last bit.
All I'm really stuck on is how to prove that if v \neq 0 why must alpha be equal to 0