oh, XD my bad! then the other guy was right.-.-
thats a diff integral
u gave us initially:
integral of (1-sqrt(x))/(1-x)
oh, XD my bad! then the other guy was right.-.-
thats a diff integral
u gave us initially:
integral of (1-sqrt(x))/(1-x)
39th Question (guesstimate.)You may have seen similar threads in other forums. In past years students have found it a great way to quiz each other on various areas of the syllabus and share their knowledge in preparation for the HSC Exams so I thought I would start one for the 2009 Mathematics students.
How To Play:
The first person asks a Mathmatics question (maybe one you've had trouble with). The next person answers it then posts another question for the next person then so on.
Tip:
If you feel an area is your weakness then try asking a question on this area to see others responses to it which may help you in your understanding.
1st Question: (Worth 3 marks in 2000 HSC)
- Find the equation of the tangent to the curve y=2logex at (1,0)
because a circle goes around forever, there is no defined beginning or end.39th Question (guesstimate.)
This is a higher-order question. Note that it requires English language rather than mathematical notation; which is not always necessary for the skilled mathematician.
Question: Explain why a circular function is equal to infinity. (And yes, there IS an answer...)
NOW no taking the piss!! Serious answer only pls .....
i)100000x1.0075^12 - MAhemed wins $100000 in a lottery. He places it in an investment account which pays 9% interest per annum compounding monthly. He plans to withdraw $M at the end of each year immediately after twelfth interest payment and he wants the investment to last 25 years.
i) Write an expression for A1, the amount of money in the account immediately after his first withdrawal of $M.
ii) Write a similar expression for A2
iii) Since A25= 0 find the value of M to the nearest dollar
i)100000x1.0075^12 - M
ii)(100000x1.0075^12 - M)x1.0075^12 - M
okay, we can make a series here. But is it both arithmetic and geometric?
It's easy but it's still 4U, this is a 2U thread if i'm not wrongeasy one...
find the mod-arg form of:
2x + 3iy=4
i dont understand; is that an equation?easy one...
find the mod-arg form of:
2x + 3iy=4
Or maybe 2Re(z)+3Im(z)=4, converted it to 2U form, thus i retract my previous statement hahamaybe she meant 2x + 3iy = z
i do MX2It's an X2 question. Don't worry about it.
easy one...
find the mod-arg form of:
2x + 3iy=4