i was gonna say just completely ignored their arctanx and its a show that q was about to fume..., the feeling of realising something so stupid after the examoh , ye nah.
hsc isn't that mean.
look i can but its gonna be on a paint.net kinda thing soooo its gonna be kinda shockingIf you download the Extension 1 and 2 syllabuses and search for the work arctan, all that pops up is "not found".
Could be a problem.
What? That sounds even more complicated. Can you draw it rather than me trying to interpret your comments and then drawing it wrong.
use siwei's mine was missing lines.What? That sounds even more complicated. Can you draw it rather than me interpreting your comments and then drawing it wrong?
nice circle
yeah take his way better lol
pretty good mouse circle considering the size nglnice circle
i wasnt being sarcasticpretty good mouse circle considering the size ngl
wait this is more correct.
yeah all ik is when you choose a point go 4 between and eventually you end up the same spotwait this is more correct.
it was 20 lines iirc.
I'm missing a few lines.
what you reckon the hardest question in that exam?wait this is more correct.
it was 20 lines iirc.
I'm missing a few lines.
perhaps the very last one.what you reckon the hardest question in that exam?
nope nothing more, just guessed honestly had no clue how to do without numbers, except mod>1 obvIf that is the case then the answer is like this:
View attachment 33782
Was there something a bit more specific about the modulus of a+ib in the question?
i had to use my ruler to measure but it was exactly modulus 7/5 from origin, so i made all my four roots roughly (7/5)^(1/4) just to be safe, so just outside the unit circleWell assuming the reconstruction is approximately correct now, it is clear firstly that the argument of the first root is a quarter that of a+ib.
Secondly that the roots are equally spaced, hence on the lines perpendicular to each other.
Thirdly that the moduli of the roots are smaller than that of a+ib, but still greater than 1.
Fourthly that since a+ib is not a real number then the roots do not occur as conjugate pairs.
Not sure how the marks would be allocated though since it is just a 2 mark question.
This is why I wanted to know more about the modulus of a+ib. If there was something more specific about that, then maybe there might be a mark associated with that too.
With this graph of