Maths Extension 2 Predictions/Thoughts (6 Viewers)

[thomas mcnamee]

I’d say that’s probably a high band e3 in this paper which is the equivalent of a ≈99.5 ATAR (depends a lot on how high though because the marks tend to fall off hard in the band 5 range)

what you reckon about 84-88

 

[carrotsss]

what you reckon about 84-88

mid band e4 which is easily a 99.95 ATAR equivalent

 

[thomas mcnamee]

like 95-97?

 

[carrotsss]

like 95-97?

yeah

 

[thomas mcnamee]

yeah

cheers mate

 

[tywebb]

nesa's version is up: https://educationstandards.nsw.edu....23/mathematics-extension-2-2023-hsc-exam-pack

 

[carrotsss]

what do u predict min e4 raw is?

it’s hard to judge impartially myself (personally I found it a bit harder than 2022 but likely due to the exam pressure) but based on what everyone is saying I’d estimate mid-high 60s

 

[kms1234]

last year scaling was quite insane. I believe a 65 went up too a 91. The general consensus from what I've heard is that this exam was as hard or at least similar to last year. Thus, I would say that 65 most likely scales up to an e4. Also, you might have forgotten carrott, but what aligned do you think a 73 would be considering that last year 76 went to a 94
(all stats are from the rawmarks database)

 

[2azn4u]

Hi everyone who somehow got a copy of my solutions, here's the most updated file with corrections on my dropbox:

https://www.dropbox.com/scl/fi/qwrq...-Mok.pdf?rlkey=idnadofksn2n9ehpi3ogtefsh&dl=0

Also, I have a video for the solution of 16.c)

 

[carrotsss]

last year scaling was quite insane. I believe a 65 went up too a 91. The general consensus from what I've heard is that this exam was as hard or at least similar to last year. Thus, I would say that 65 most likely scales up to an e4. Also, you might have forgotten carrott, but what aligned do you think a 73 would be considering that last year 76 went to a 94
(all stats are from the rawmarks database)

As I said it’s quite hard for me impartially judge the difficulty given that I say the past hsc exams in more laid back (though still timed) conditions, but I think that as a paper it was slightly easier than 2022, hence the mid-high 60s cutoff estimation. Hence, a 73 should be 91-93 (though I’d lean more towards the lower side of that)

 

[kms1234]

Carotsss I dont know who you are, but you are the only god that I worship

 

[kms1234]

Both fizzysoda and mok's solutions used different methods to get to the answer. Would the hsc cater to the variety of different methods used. I am a but worried that my answer may deviate from the worked solutions

 

[carrotsss]

Both fizzysoda and mok's solutions used different methods to get to the answer. Would the hsc cater to the variety of different methods used. I am a but worried that my answer may deviate from the worked solutions

That’s fine as long as you used a valid method

 

[tywebb]

Both fizzysoda and mok's solutions used different methods to get to the answer. Would the hsc cater to the variety of different methods used. I am a but worried that my answer may deviate from the worked solutions

This is extension 2 right? Multiple valid methods are plentiful in extension 2, maybe less so in the Standard courses.

So there are no surprises that there be variations in methods for extension 2 solutions.

 

[tywebb]

epicmaths solutions is at https://community.boredofstudies.or...ing-it-for-the-first-time.405811/post-7513591

It's a pdf made from last night's live youtube. The youtube goes for 3 hours 18 minutes and 14 seconds.

Here is the youtube:

 

[Allan Mekisic]

Alternative solution to 16(c)

 

[notme123]

another solution to question 16c:

xz + yw has to be an obtuse rotation away from z which is a region spanned by the complex numbers iz and -z. in x and y, this is somewhere in the third quadrant which would be easier to show with a diagram but i cbb just take it as fact.

let a and b be positive real numbers.

the first boundary of this region is that zx+yw = -az where a is positive real --> x + y*w/z = -a
Taking imaginary parts, y*Im(w/z) = 0 --> y = 0
Taking real parts x + y*Re(w/z) = -a --> x = -a, meaning that x < 0 since a is positive real.
Hence one of the boundaries of the region is the line y = 0, x < 0 or the x axis on the left of the cartesian plane'
Another way to do this step is looking at zx+yw = -az, z and w are linearly independent vectors so you can instantly go to x = -a and w = 0.

the second boundary of the region is zx+yw = -biz where b is positive real --> x + y w/z = -bi
Taking real parts --> x + y*Re(w/z) = 0 --> y = -x/Re(w/z) --> |y| = |-x/Re(w/z)| --> -y = -x/|Re(w/z)| --> y = x/|Re(w/z)| where x < 0, y < 0

The complete solution is the region bounded by S = { (x,y) \in R^2 : y < 0, x < 0, y > x/|Re(w/z)|}

 

[Sam_Smythe]

omg yay i got 4/10 in mc (i thought i got 3)

Got 4 as well lmao that's not good is it?

 

[Hudz777]

me being rank 1 of 1 (failed the exam tho anyways...)

aye same, absolutely bummed it. Even stuffed up the partial fractions… idk how, I wrote 2ln2 - 3ln3 instead of 2ln3 - 3ln3. I’m actually done.

 

[sneak11]

does anyone know how the 4marks in the partial fraction integration in q11 might have been allocated - like what would u need to do to get each mark?