R rolror88 Member Joined Jul 19, 2008 Messages 240 Gender Male HSC N/A Nov 10, 2008 #1 Someone asked me this SC question and I'm completely stumped lol. Can anyone figure it out? a, b and c are three different positive integers, and (ab)sqaured = abc whats the value for c? a) 1 b) 5 c) 9 d) 12
Someone asked me this SC question and I'm completely stumped lol. Can anyone figure it out? a, b and c are three different positive integers, and (ab)sqaured = abc whats the value for c? a) 1 b) 5 c) 9 d) 12
K kmlb123 New Member Joined Nov 9, 2008 Messages 5 Gender Male HSC 2010 Nov 10, 2008 #2 (ab)^2 = abc therefore ab=c (divide both sides by ab) If c=1 then a and b = 1 (a,b,c are three DIFFERENT values) If c =5 then a b = 1, 5 (look above) If c= 9 then ab= 3,3 OR 1,9 (Look above) therefore c must = 12 and b,c = 3,4 or 2,6
(ab)^2 = abc therefore ab=c (divide both sides by ab) If c=1 then a and b = 1 (a,b,c are three DIFFERENT values) If c =5 then a b = 1, 5 (look above) If c= 9 then ab= 3,3 OR 1,9 (Look above) therefore c must = 12 and b,c = 3,4 or 2,6
R rolror88 Member Joined Jul 19, 2008 Messages 240 Gender Male HSC N/A Nov 10, 2008 #3 Thanks. I worked it out by substitution and removing answers; Your way is way faster.
