S Starrzz Member Joined May 14, 2009 Messages 35 Gender Male HSC 2011 Mar 7, 2010 #1 I am quite confused about these questions, and don't know how to go about doing them. Help would be appreciated 1. 2. 3.
I am quite confused about these questions, and don't know how to go about doing them. Help would be appreciated 1. 2. 3.
SeCKSiiMiNh i'm a fireball in bed Joined Mar 6, 2008 Messages 2,618 Location island of screaming orgasms Gender Male HSC 2009 Mar 7, 2010 #2 Starrzz said: I am quite confused about these questions, and don't know how to go about doing them. Help would be appreciated 1. Click to expand... 1. f(x)= 5x - x^2 f(x + h) = 5(x+h) - (x+h)^2 therefore, f(x +h) - f(x) = [5(x+h) - (x+h)^2] - [5x - x^2] = 5x + 5h - (x^2 + 2xh + h^2) - 5x + x^2 = 5h - x^2 - 2xh - h^2 + x^2 = -h^2 - 2xh + 5h
Starrzz said: I am quite confused about these questions, and don't know how to go about doing them. Help would be appreciated 1. Click to expand... 1. f(x)= 5x - x^2 f(x + h) = 5(x+h) - (x+h)^2 therefore, f(x +h) - f(x) = [5(x+h) - (x+h)^2] - [5x - x^2] = 5x + 5h - (x^2 + 2xh + h^2) - 5x + x^2 = 5h - x^2 - 2xh - h^2 + x^2 = -h^2 - 2xh + 5h
adomad HSC!! Joined Oct 10, 2008 Messages 543 Gender Male HSC 2010 Mar 7, 2010 #3 all you need to do for the first one is sub in (x+h) for every x so if f(x)=5x-x^2. f(x+h)= 5(x+h)-(x+h)^2. when you minus the f(x) you just do normal algebra and the other questions are similar
all you need to do for the first one is sub in (x+h) for every x so if f(x)=5x-x^2. f(x+h)= 5(x+h)-(x+h)^2. when you minus the f(x) you just do normal algebra and the other questions are similar
SeCKSiiMiNh i'm a fireball in bed Joined Mar 6, 2008 Messages 2,618 Location island of screaming orgasms Gender Male HSC 2009 Mar 7, 2010 #4 Starrzz said: I am quite confused about these questions, and don't know how to go about doing them. Help would be appreciated 2. Click to expand... f(x) = x^2 + 4x -5 f(x+h) = (x + h)^2 + 4(x+h) - 5 therefore, f(x+h) - f(x) = (x^2 + 2xh + h^2) + 4x + 4h - 5 - x^2 - 4x +5 2xh + h^2 +4h on the 2nd part, simply divide everything in part 1 by h which equals : 2x + h + 4
Starrzz said: I am quite confused about these questions, and don't know how to go about doing them. Help would be appreciated 2. Click to expand... f(x) = x^2 + 4x -5 f(x+h) = (x + h)^2 + 4(x+h) - 5 therefore, f(x+h) - f(x) = (x^2 + 2xh + h^2) + 4x + 4h - 5 - x^2 - 4x +5 2xh + h^2 +4h on the 2nd part, simply divide everything in part 1 by h which equals : 2x + h + 4
D demikid New Member Joined Feb 8, 2010 Messages 13 Location Sydney Gender Male HSC 2011 Uni Grad 2015 Mar 10, 2010 #5 These questions seem soooo familiar - I did exactly the same questions for maths just a week ago.. Any chance we in the same class? haha
These questions seem soooo familiar - I did exactly the same questions for maths just a week ago.. Any chance we in the same class? haha
S Starrzz Member Joined May 14, 2009 Messages 35 Gender Male HSC 2011 Mar 11, 2010 #6 demikid said: These questions seem soooo familiar - I did exactly the same questions for maths just a week ago.. Any chance we in the same class? haha Click to expand... Haha, doubt it, I would know if we were in the same class =P I understand now how to do these types of questions, if I have more questions I will be back. Thank you for all the help.
demikid said: These questions seem soooo familiar - I did exactly the same questions for maths just a week ago.. Any chance we in the same class? haha Click to expand... Haha, doubt it, I would know if we were in the same class =P I understand now how to do these types of questions, if I have more questions I will be back. Thank you for all the help.