Modifying arbitrary constant for differentials (1 Viewer)

[xibu34]

Is it necessary to modify the constant like Cambridge in the HSC, or could you just remove the absolute value brackets without any annotations ?

 

[cossine]

Is it necessary to modify the constant like Cambridge in the HSC, or could you just remove the absolute value brackets without any annotations ?
View attachment 39699

I would mention A can be positive or negative. It is better to communicate.

 

[xibu34]

I would mention A can be positive or negative. It is better to communicate.

On the topic of differentials, what do they mean by "dividing through" here ? Do they just multiply by 1/Ae^Pkt, and if so then how does the exponent in the denominator become -Pkt

 

[synthesisFR]

On the topic of differentials, what do they mean by "dividing through" here ? Do they just multiply by 1/Ae^Pkt, and if so then how does the exponent in the denominator become -Pkt
View attachment 39700

They divided through by Ae^pkt to get from the second last line to the last line.


Oh btw. I hate doing the replacing thing with that they are talking about. What u do to avoid this is:

View attachment 39699

U see the equation on the third last one with the log? Just flip it so that the P-N bit is on the top. Do this by removing the negative from the log. Then it’s simpler to like convert to the form u require.

 

[synthesisFR]

Like so
Keep c positive it’s just a constant and define A as +-e^c

 

[carrotsss]

Like soView attachment 39701
Keep c positive it’s just a constant and define A as +-e^c

yeah I do the same I feel like it’s a lot less confusing

 

[Luukas]

Is it necessary to modify the constant like Cambridge in the HSC, or could you just remove the absolute value brackets without any annotations ?
View attachment 39699

If you do make the change from the constant being C to it being A, I think the important point is that C can be any real number but A is restricted to being a non-zero real.