• Congratulations to the Class of 2024 on your results!
    Let us know how you went here
    Got a question about your uni preferences? Ask us here

More circular motion questions (1 Viewer)

byakuya kuchiki

New Member
Joined
Sep 15, 2008
Messages
29
Gender
Male
HSC
2010
Given that a string (0.6m in length), can only sustain a mass of 10kg, find the fastest speed (in rpm) that the string can be rotated (in a horizontal circle) if the mass at the end is 0.2kg?
(*g is specified as 9.8m/s^2)

help is appreciated!!
 

Trebla

Administrator
Administrator
Joined
Feb 16, 2005
Messages
8,401
Gender
Male
HSC
2006
Given that a string (0.6m in length), can only sustain a mass of 10kg, find the fastest speed (in rpm) that the string can be rotated (in a horizontal circle) if the mass at the end is 0.2kg?
(*g is specified as 9.8m/s^2)

help is appreciated!!
The string can sustain a mass of 10kg vertically which is equivalent to 10 x 9.8 = 98 Newtons
Assuming that the only force acting on the mass is centripetal force:
F = mrω²
Substituting the maximum force it can sustain and the relevant information:
98 = 0.2 x 0.6 x ω²
Solve for ω and convert to relevant units
 

Lukybear

Active Member
Joined
May 6, 2008
Messages
1,466
Gender
Male
HSC
2010
The string can sustain a mass of 10kg vertically which is equivalent to 10 x 9.8 = 98 Newtons
Assuming that the only force acting on the mass is centripetal force:
F = mrω²
Substituting the maximum force it can sustain and the relevant information:
98 = 0.2 x 0.6 x ω²
Solve for ω and convert to relevant units
Havent done 4unit circular motion yet, but from physics, i thought centripedal force was F=mv^2/r.
 

jet

Banned
Joined
Jan 4, 2007
Messages
3,148
Gender
Male
HSC
2009
They're the same thing. v = rω, so substituting in yields the same expression/
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top