motion question (1 Viewer)

[Hermes1]

the acceleration of a particle released from rest from the origin is given by the above equation,

prove that the particle ultimately moves between two points on the x-axis and find these points.

eventually i got:

is this correct

 

[Hermes1]

also could someone give me the method they used to solve it

 

[cutemouse]

[maths]\text{Use } \ddot{x}=\frac{d}{dx} \left( \frac{1}{2} v^2 \right)[/maths]

 

[Hermes1]

[maths]\text{Use } \ddot{x}=\frac{d}{dx} \left( \frac{1}{2} v^2 \right)[/maths]

yeh i did, and i got an expression for v^2 and graphed that against x. then i just took the parts where v^2 greater than or equal to zero. is this the only way to do the question?

 

[kooliskool]

yep, that's right.