MedVision ad

Multiple Choice Answers (1 Viewer)

ramanij

Member
Joined
Feb 10, 2004
Messages
53
what did everyone fink of chem hard, ezy, ok? i found that there was too much skill-based questions
 

joca187

New Member
Joined
Feb 23, 2004
Messages
20
Gender
Male
HSC
2004
It seems that every has put 9A as the answer, but since the empirical formula means that 1 - 1 - 1 - 1, it means that a maximum of 0.66g of Ozone can react with the NO, therefore 0.66g/30 - which is the molar mass of NO, x22.71 equals 0.5L. thats how I interpreted it anyway
 

mazza_728

Manda xoxo
Joined
Jun 2, 2003
Messages
755
Location
Sydney - Sutherland Shire
Gender
Female
HSC
2004
if those are right i got 15/15 also which i would love :D dont get my hopes up guys... i cant take anymore let downs!! i got 15/15 right? ...right guys? ..........guys? awww not again :(
 

mervvyn

Marshm'ello
Joined
Aug 7, 2004
Messages
537
Location
Somewhere over the rainbow... yes, that rainbow.
Gender
Male
HSC
2004
joca187 said:
It seems that every has put 9A as the answer, but since the empirical formula means that 1 - 1 - 1 - 1, it means that a maximum of 0.66g of Ozone can react with the NO, therefore 0.66g/30 - which is the molar mass of NO, x22.71 equals 0.5L. thats how I interpreted it anyway
Explanation of 9 and why it is (A):

0.66g NO is 0.022 mol
0.72g O3 is 0.015 mol

given that it is 1-1-1-1, ozone is the limiting reagent
therefore 0.015 mol of NO2 produced * 22.71 = 0.34L --> A
 

Gesus

Member
Joined
Feb 17, 2004
Messages
62
Location
Where abouts are you located?
Gender
Male
HSC
2004
joca187 said:
It seems that every has put 9A as the answer, but since the empirical formula means that 1 - 1 - 1 - 1, it means that a maximum of 0.66g of Ozone can react with the NO, therefore 0.66g/30 - which is the molar mass of NO, x22.71 equals 0.5L. thats how I interpreted it anyway
Yeah, this was pressed so hard by my teachers in yr11, in chemistry, only moles can be compared, not mass
 

nemo-42wy

New Member
Joined
Oct 1, 2004
Messages
7
Location
Northern Beaches
Gender
Male
HSC
2004
1) A
2) A
3) B
4) A (but i know it's wrong now. what's an allotrope?)
5) C
6) C
7) D
8) Can't remember but know i got it wrong
9) A
10) C
11) A
12) C
13) C
14) D (total guess!)
15) A (stupid, stupid mistake!)

Good luck peoples in the rest of all your exams!!!
 

beccabum

hung up
Joined
Feb 25, 2004
Messages
92
Location
in the outer suburbs of the middle of nowhere
Gender
Female
HSC
2004
ohhhh i feel so dumb! I think I only got about 10, after looking over the qs and from reading all your answers. For shits + giggles, here they are:
1A
2C (whoops)
3B
4B
5D ??
6D
7D
8D
9D
10A
11A
12B (total guess)
13A
14C
15B or C, can't remember, I guessed it

Hope you guys went ok in everything
best of luck in all your other subjects
 

lucyinthehole

Member
Joined
Feb 23, 2004
Messages
256
yeah i got 10 :( bah.... isomers/allatropes.... who knows what they are? anyone with 5 braincells, that's who!!! how could i forget??
 

alex tonkin

New Member
Joined
Aug 30, 2004
Messages
20
i know these ones are correct...

1.a
2.a
3.b
4.b
5.c
6.d
7.d
8.d
9.
10.c
11.a
12.
13.
14.d
15.b all of my mates answers seemed to vary on the calculation ones and wat the fuck was 12?
 

martian_man86

New Member
Joined
Jul 24, 2004
Messages
6
heres mine:

1a
2a
3b
4b
5c
6d
7d
8d
9a
10c
11a
12 i put c, but im not 100% sure...im pretty sure the ammonium ion has a coordinate covalent bond
13c
14d
15b
 

NeRdY

Member
Joined
Jun 5, 2003
Messages
43
Location
la-la land
Gender
Female
HSC
2004
1. A
2. A
3. B
4. B
5. C
6. D
7. D
8. D
9. D
10. C
11. A
12. C
13. B (my answers didnt match up to any so guessed)
14. D
15. B
 

crazed_fairy

New Member
Joined
Feb 11, 2004
Messages
5
q5 is c coz it asked wats davy's theory, not the current theory. he was the dude that sed acids must have hydrogen
 

GirlGoneMad

Kitten Kong
Joined
Mar 13, 2004
Messages
220
Location
Far, far away
Gender
Female
HSC
2004
1a
2a
3c
4b
5a
6d
7d
8d
9b
10c
11a
12b
13a
14a
15b

They are mostly wrong and some I didn't remember so I just guessed what i had chosen.
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top