• Congratulations to the Class of 2024 on your results!
    Let us know how you went here
    Got a question about your uni preferences? Ask us here

Need help with partial fractions integral question (1 Viewer)

Zorren

New Member
Joined
Mar 9, 2014
Messages
19
Gender
Male
HSC
2015
Hey guys,

I'm looking for a little bit of assistance with a question. Any help would be really appreciated! Its question 1D. Thanks in advance
 

integral95

Well-Known Member
Joined
Dec 16, 2012
Messages
779
Gender
Male
HSC
2013
it needs to be in the form




times both sides by (x-1)^2(x+1)^2 and equate coefficient.

So you start by getting



Sub in x = -1 and x = 1 (seperately) to get B and D respectively

Equate X^3 coefficient to get A+C = 0

equate constants to get -A+B+C+D = 4

and use simult equation to find A and C (that's after you found B and D of course)
 
Last edited:

Zorren

New Member
Joined
Mar 9, 2014
Messages
19
Gender
Male
HSC
2015
Thank you very much for your response I understand your working. But may I ask why did split the fraction into 4 components rather than 2 at the start?
 

integral95

Well-Known Member
Joined
Dec 16, 2012
Messages
779
Gender
Male
HSC
2013
Hmm I don't remember the reason behind that tbh

might need to ask someone else this (anyone?? )
 

seanieg89

Well-Known Member
Joined
Aug 8, 2006
Messages
2,662
Gender
Male
HSC
2007
Thank you very much for your response I understand your working. But may I ask why did split the fraction into 4 components rather than 2 at the start?
Whenever there are factors with multiplicity > 1 in the denominator you will need to do this.
 

Zorren

New Member
Joined
Mar 9, 2014
Messages
19
Gender
Male
HSC
2015
Yeah I've just worked it out, you have to square the denominators to get up with the same denominator of the original fraction
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top