second question:
ionisation involves the basic equation: HA + H2O ⇌ H3O+ + A- (reversible because citric acid is a weak acid, and *one* hydronium ion/hydrogen ion is being 'removed' for each ionisation). using this for citric acid, start with the dissociation of a citric acid molecule:
1st: C6H8O7 + H2O ⇌ H3O+ + C6H7O7- (1st ionisation - take away one hydrogen from the formula of citric acid, which becomes the hydrogen ion/hydronium ion, then minus that hydrogen so now there's 7 hydrogens in the formula left. since you've taken out a hydrogen, you need to compensate for that by putting a minus indicating that it's now become a charged ion
2nd: C6H7O7- + H2O ⇌ H3O+ + C6H6O7(2-) (2nd ionisation - same thing with above, but now the -1 charge becomes -2 because you've taken one hydrogen out, now the particle has 6 hydrogens left)
3rd: C6H6O7(2-) + H2O ⇌ H3O+ + C6H5O7(3-) (3rd ionisation - same thing with above, but now the -2 charge becomes -3 because you've taken one hydrogen out, now the particle has 5 hydrogens left)
for a strong acid, the ionisation is an irreversible one and thus has this arrow [-->]. however, if it's monoprotic, its successive ionisations will be with substances that aren't strong acids and hence their ionisations following that of the first one are reversible like the citric acid ones i showed above
(edit: made an edit because i mistakenly said that H3PO4 was a strong acid. it's weak)