needs some background knowledge >< (1 Viewer)

[fullonoob]

ZOMGOASFASDBASHFDB...........
kept letting u = the top part >< didnt think letting u be on the bottom would get anything but i was wrong :<

 

[fullonoob]

if you are not comfortable with this approach,

d(sqrt x)/dx = 0.5/sqrt x ==> dx/sqrt x = 2 d(sqrt x)

what does this mean "dx/sqrt x" i don't quite understand the language
d / dx = differentiate dx / d = integrate?

 

[randomnessss]

wow thanks a lot didnt think of changing the indices
i have another one, it made me rage quit cos i used so many ways and ended up nowhere....



please help

 

[Drongoski]

what you would normally do is:

 

[fullonoob]

if the graph of the function y = ce^-bx has intercepts y(0) = 1 and y(1) = 0, show that y = [e^(b-bx) - 1)] / (e^b - 1)
last question for the day

 

[shaon0]

if the graph of the function y = ce^-bx has intercepts y(0) = 1 and y(1) = 0, show that y = [e^(b-bx) - 1)] / (e^b - 1)
last question for the day

I don't think the question is correct as y(1)=c.e^-b=0 but e^-b=/=0

 

[fullonoob]

b can be infinite ?

 

[shaon0]

b can be infinite ?

Yeah probably, but it's a pretty funky question.

 

[fullonoob]

ya 3 unknowns
i got 2 equations, dno how to make the 3rd one (maybe integrate or differentiate the original).
Ill try tmr, too tired now