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Parametric Equations of the Parabola (2 Viewers)

FDownes

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Thanks. Now time for another;

How can I solve the two equations x + py = p3 + 2p and x + qy = q3 + 2q simultaneously to find the point of intersection (-pq(p + q), p2 + q2 + pq + 2)?

EDIT: Never mind, got it. Thanks again Tommy. :)
 
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FDownes

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I'd like to double check my working for this question to make sure I have it right;

a) Write down the equation of the chord joining the points P (2ap, ap2) and q (2aq, aq2) on the parabola x2 = 4ay.

[I think I've got this working down. I'm not sure if it should plus apq or minus apq in the final equation though...]

= m = [(ap2) - (aq2)]/[(2ap) - (2aq)]
= m = [a(p2 - q2)]/[2a(p - q)]
= m = [a(p - q)(p + q)]/[2a(p - q)]
= m = (p + q)/2
= [y - (ap2)] = [(p + q)/2][x - (2ap)]
= y - ap2 = [x(p + q)/2] - [2ap(p + q)/2]
= y - ap2 = 1/2(p + q)x - ap2 - apq
= y = 1/2(p + q)x - apq

b) Show that if PQ is a focal chord then pq = -1

= focus = (0, 1)
= 1 = 1/2(p + q)(0) - (1)pq
= -pq = 1
= pq = -1

c) Find the equation of the tangent at P and the coordinates of T, the point of intersection of the tangents at P and Q. Hence determine the equation of the locus of T as P and Q vary.

[For this question and the one below I have some attempted working, but it's fairly messed up. I'd like to check it by comparing it to someone elses working, if they could post it here. The tangent for P should be y - px + ap2 = 0, and likewise the tangent for Q should be y - qx + aq2 = 0. The coordinates of T are
[a(p + q), apq].]

d) Find the equation of the normal at P and the coordinates of N, the point of intersection of the normals of P and Q. Hence determine the equation of the locus of N.
 

FDownes

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Hmm... I followed a similar process when trying to figure out c), but couldn't get the correct answer. According to the sheet, the locus of T should be y = -a (i.e. the directrix).

While I'm here I may as well post the the answers to d) as well. N should be [-apq(p + q), a(p2 + pq + q2 + 2)], and have a locus of x2 = a(y - 3a). This is from the sheet, not from my own working.
 

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