Parramatta Marist 2020 - Mex2 Paper (1 Viewer)

[Pedro123]

2 Questions:
1) is Q22 a) correct, because I'm under the impression it should be 100j (Instead of j) in the given equation
2) How exactly do you go about showing Q23? I imagine it is insufficient to show the integral approaches 0 as n approaches infinity, therefore there will always exist an n. I originally tried transforming the RHS to the integral of x^(r-1) from 1-0, but didn't know where to go from there.

Thanks

 

[Pedro123]

Actually on the second question, is the method: (Apologies for not using right formatting):
- Integration by parts on the middle one, which gets the inequality (As it is greater than 0 by inspection) I_(n-1) < e/n
- Using this to show er < n+1
- There will always be an n to fulfill this