Run hard@thehsc
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Phys q on kepler (1 Viewer)
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Run hard@thehsc
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Can someone explain the reasoning behind this - the derivation is straight forward
ExtremelyBoredUser
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reasoning for what? Do you want to see how it is solved?
ExtremelyBoredUser
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excuse my paint.net artistry
periapsis is the position which has the least distance between the focus and itself. consequently this is a - c.
apoapsis is the position which has the most distance between the focus and itself. this is a + c
e = c/a (eccentricity)
r_p = a - ea = a(1-e)
r_a = a + ea = a(1+e)
, r_{a} = a(1+e) )
and the ratio of p to a is simply Rp/Ra
If you want reasoning how the radius equation is found
periapsis is the position which has the least distance between the focus and itself. consequently this is a - c.
apoapsis is the position which has the most distance between the focus and itself. this is a + c
e = c/a (eccentricity)
r_p = a - ea = a(1-e)
r_a = a + ea = a(1+e)
and the ratio of p to a is simply Rp/Ra
If you want reasoning how the radius equation is found
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Run hard@thehsc
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@ExtremelyBoredUser thanks man - was straight forward - was just confused if it was just this alone or not