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Polynomial help please! (1 Viewer)

aoniumz

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When a polynomial is divided by (2x+1)(x-3), the remainder is 3x-1. What is the remainder when the polynomial is divided by 2x+1
 

Carrotsticks

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Hint: Since we are dividing by a quadratic, the remainder will be in the form ax+b, where a and b can be any real numbers.
 

aoniumz

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P(x) = (2x+1)(x-3) Q(x) + 3x-1

P(x)= (2x+1) Q(x) + ax+b

idk what I am doing o_O
 
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MrBeefJerky

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Correct me if I'm wrong, but don't u just sub P(-1/2) into P(x)=(2x+1)(x-3)Q(x)+3x-1
 
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Carrotsticks

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Oh sorry, I mis-read your question. It's a lot simpler than I had originally thought. I processed it as one of those typical 'When P(x) is divided by (2x-1) the remainder is 3, when P(x) is divided by (x+1) the remainder is -1, what is the remainder when P(x) is divided by (2x-1)(x+1) etc', where the usual step would be to let the remainder by ax+b.

P(-1/2) = 0 + 3(-1/2)-1 since P(x) = (2x+1)(x-3) Q(x) + 3x-1.
 

aoniumz

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Well, answer at the back of my book says 1/2 lol
and yes the question I posted is the right question..
 

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